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D = R*TT = D/RR = D/TThe boat going downstream covers the same distance as if it were going upstream but at a faster time. I think her answer is incorrect.
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From my understanding, she's saying that the boat will move faster in still water.
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Total Distances of both trips = 288. Now for Ds, we know that the rate must have been double. So we understand the Current to be the Ds Rate of 12 divided by 2. which gives you 6.
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Warning I may be Wrong! Ds=Downstream Us= UpstreamDs = 12x = 288/2 ==> x =12 | Us = 36x = 288/2 ==> x = 4 Therefore Ds = 12*12 = Distance of 144 & Us = 4*36 = Distance of 144 ==> 144+144
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In this Question there are 2 Unknowns. The Time both Planes traveled and their distances respectively.
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Initially she started off with attempting to find THE TIME, which is distance over rate. Hence D1/R1 and D2/R2. Is it that 1304.3 represents the time and not the distance±
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