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# Work-Energy Theorem

###### Matt Jones

###### Matt Jones

**M.Ed., George Washington University**

Dept. chair at a high school

Matt is currently the department chair at a high school in San Francisco. In his spare time, Matt enjoys spending time outdoors with his wife and two kids.

According to the **work-energy theorem**, the net work on an object causes a change in the kinetic energy of the object. The formula for net work is *net work = change in kinetic energy = final kinetic energy - initial kinetic energy*.

The work energy theorem, this is a theorem that states the net work on an object causes a change in the kinetic energy of the object. So let's review kinetic energy, remember kinetic energy which we'll abbreviate ke is one half the mass times the velocity squared okay. So the net work is the change in kinetic energy or the final kinetic energy minus the initial kinetic energy. Let's look at a problem where you might be asked to use the work energy theorem to solve a problem related to net work okay. Let's say I've got an object of 3, a mass of 3 kilogram object and I need to accelerate it from 2 meters per second to 4 meters per second. And I want to know what the net work is needed to cause that acceleration okay. So I can use this formula where net work equals my final kinetic energy minus my initial kinetic energy.

Let's go ahead and solve for that problem alright? So my final kinetic energy is one half and my mass is 3 kilograms and my final velocity is 4 meters per second squared right? My initial velocity is, and so my initial kinetic energy is 3 kilograms times 2 meters per second squared alright, so let's go ahead and crunch these numbers and I got to have my one half times that, let's fix that before we move on. So I've got 4 squared is 16 times 3 is 48 and one half of 48 is 24 kilograms over meters per second squared and I'm going to subtract from that I've got 2 squared is 4 meters per second squared and times 3 is 12 and minus one half of 12 is 6 kilograms and if I subtract 6 from 24 I get 18 and this also equals this unit here kilograms over meters over seconds squared equals 18 joules of energy. So that is my net work that is required to accelerate that object from 2 meters per second to 4 meters per second. So this is how you might solve a problem applying the theorem of work energy theorem.

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###### Matt Jones

M.Ed., George Washington University

Matt is very comfortable in front of the whiteboard and is able to make every topic easy for anyone to digest. His straightforward approach to teaching is very refreshing.

## Comments (1)

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## amari · 7 months, 2 weeks ago

Thanks so much, This was very helpful