### Learn math, science, English SAT & ACT from

high-quaility study
videos by expert teachers

##### Thank you for watching the preview.

To unlock all 5,300 videos, start your free trial.

# Power

###### Jonathan Osbourne

###### Jonathan Osbourne

**PhD., University of Maryland**

Published author

Jonathan is a published author and recently completed a book on physics and applied mathematics.

**Power** is the rate of energy use of electric circuit. The way that we calculate power is through the equation *power = current x potential difference = (potential difference)^2/resistance = current^2 x resistance*.

Alright so let's talk about power in electric circuits alright the idea is that in order for me to get current to flow through a resistor or really through any circuit at all I've got to give it some energy. I need energy to drive current through the circuit and that's actually the purpose of the battery. The battery is going to supply energy, now obviously if you got the circuit running for longer you're going to use more energy. So it's more useful for us to go to power which is rate of energy use, alright so let's start off with energy equals charge times potential difference and that's just basically the definition of potential difference. So but that's energy what about power? Well power is energy per unit time so when I divide by time I'm going to associate that division with the charge, so I'll get charge divided by time times potential difference. But charge divided by time is the current so that gives us the most basic and simple expression for power p equal iv current times potential difference.

This is often the one that you want to use if you're interested in how much power is being supplied to a circuit by a battery. So let's take an example 4 amps of current are running through a 12 volt battery so that 12 volt battery is pushing 4 amps of current and I want to know hw much power is delivered to the circuit by the battery. Well power equals iv so I got 4 times 12, 48 watts notice again we're doing everything in SI units and that means everything is in SI units. So if it's a power it's watts alright now most of the time when we're asking about power we're really thinking about resistors. So what we can do is we can re-write this standard formula using ohms law because current is v over r so that means that I can also write power as v squared over r. I also know that potential difference is current times resistance, so that means that I can also write it as i squared r. These are the 3 basic formulas that you'll see most often on introductory Physics tests and they're real, real easy to remember.

The first one power equals iv like a hospital, second one v squared over r you ought to recognize that formula from centripetal acceleration you're going in circle with radius r at speed v you require an acceleration v squared over r. Now this v of course is potential difference and this r is resistance. But it still sounds the same so it makes it easy to remember but this last one I didn't have a good way to remember this one until a student of mine about 6 years ago said that she'd heard somewhere twinkle, twinkle little star power equals i squared r which I just thought was great so those are real, real simple ways to remember these formulas which one do I use? Well that depends on which information I have. Most of the time I have the resistance so I don't want to use iv, okay because then I've go calculate something that they didn't even give me for free right? So I'd like to use this one if I know the potential difference and this one if I know the current.

Alright let's see how this goes, suppose that I've got a circuit like this one and I want to know how much power is used in this 2 ohm resistor right here alright really simple. This 2 ohm resistor is in parallel with the battery so that means the potential difference across it is 6 volts see? Potential difference is 6, resistance is 2 so what do we got? 6 squared over 2, v squared over r 18 watts alright. What about this 1 ohm resistor here alright this is a little bit more complicated because I don't know the potential difference across it so what I need to do because this 1 ohm is in series with the 2 ohm resistor is I need to calculate the current. Because current is the same in series alright so 6 volts dropped over a total of 3 ohms so that means the current is 2 amps alright now I know the current I know the resistance so I'm going to use my twinkle, twinkle little star. i squared r so it's 2 squared times 1 4 watts alright what about in this 2, well in this 2 it'll be same current so it'll be 2 squared times 2 so that's 8 watts in the other 2 ohm and if I add it all together I get 18 plus 4 plus 8 and that's 30 watts total that's being supplied. Alright now let's check that out, let's just check that out because it's always useful to go through all the Math and make sure that we're good alright. So I got 2 amps coming here how many amps do I have coming here? Well 6 divided by 2 is 3 so I got 3 amps in this arm, 2 amps in this arm so how many amps are going through the battery? 5 because we got to add them together so the 5 come in 3 go down over here and 2 go over here alright.

I've got a battery 6 volts current 5 amps so how much power is this batter giving the circuit? iv 5 times 6 is 30 watts in agreement with what we got down here for the total power that's used. It has to work that way power in equals power out alright. Now one other important thing to think about when you're thinking about power is that when you've got resistors connected in series the current is the same, so that means that I'm looking at i squared r. So that means the bigger the resistor the more power r big power big. So the smallest resistor in series will use the smallest amount of power alright. You might think why I'm I even saying that? In parallel it works a different way, in parallel it's the potential difference that's the same not the current. So in parallel I don't use i squared r because I don't know i I use v squared over r and that means that in parallel the smallest resistor uses the most power okay and that's counterintuitive but it's true. So resistance goes up power goes down the biggest resistor in a parallel combination uses the smallest amount of power and one real simple way to think is that you don't want to take a paper clip and stick it into an outlet. Why? Real small resistance on a parallel circuit equals huge amount of power and your circuit breaker's blow. Alright that's power.

Please enter your name.

Are you sure you want to delete this comment?

###### Jonathan Osbourne

PhD., University of Maryland

He’s the most fun and energetic teacher you’ll ever meet. He makes every lesson sound like the most exciting topic ever so you never get bored when he's teaching.

#### Related Topics

- Conservation of Charge - Electric Charge 31,803 views
- Charge Transfer - Electroscope 21,297 views
- Electric Force - Coulomb's Law 24,819 views
- Electric Fields 22,621 views
- Electric Potential 23,025 views
- Electrons - Quantization of Electric Charge 17,850 views
- Conductors 11,837 views
- Insulators 9,628 views
- Electric Current 20,872 views
- Resistance 11,847 views
- Potential Difference 20,711 views
- Ohm's Law 17,066 views
- Electric Circuits 15,943 views
- Resistors in Series 13,636 views
- Resistors in Parallel 15,002 views
- Resistor Circuits 12,969 views
- Capacitors 15,525 views
- Capacitors in Series 12,106 views
- Capacitors in Parallel 10,582 views
- Capacitor Circuits 11,928 views
- RC Circuits 19,959 views

## Comments (1)

Please Sign in or Sign up to add your comment.

## ·

Delete

## mohammad · 1 year, 3 months ago

In a question its given that a heater has power of 3800 W. Does this mean 3800J of energy is being transferred per second?