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Find the extreme values of the function g(x)=sqrt(4-x^2)

p031

by p031 at May 22, 2011

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Take the derivative and set it equals to zero, to find critical points.[-x/sqrt(-x^2+4)]=0the only solution is 0, so plug in zero in the original function.You will end up with one critical point, (0,2).Test the limit as the variable x of the derivative reaches +zero, and - zero.you will find out that the value of g(0) is an extrema, that is a maximum value for g(x) at x=0.

Ahmed_Alramadhan Ahmed_Alramadhan May 23, 2011

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Critical values also occur at values of x that cause the denominator to equal zero.For this problem, x=2 and x=-2 are also "critical values", so examine those points too.Also, the derivative is:Hope that helps

Steve204 Steve204 May 23, 2011

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Find the critical points by finding the first derivative and equating it to o and also when the first derivative is undefined. These are the extreme values

chitra003 chitra003 May 23, 2011

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