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A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 16 m/s. If the brick is in flight for 3.4 s, how tall is the building in meters?

Michael1090

by Michael1090 at May 21, 2011

the 35 A is 35 degrees....sorry for the typo

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Resolve the velocity vector 16 m/s into x and y component.The y component is 16*sin35This is the initial vertical velocityThe time is 3.4 secuse the kinematic equation d=v(i)t+.5gt^2g=-9.8m/s^2v(i)=16*sin35solve for d which is the displacement, and that is the height of the building

chitra003 chitra003 May 21, 2011

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i think i would be dead before i calculated that.

Andes.person Andes.person May 23, 2011

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