6n(3n+8)+12(n-9)

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1) Distribute: 6n(3n+8) +12(n-9) so 6n(3n) + 6n(8) + 12(n) + 12 (-9)     18n^2 + 48n + 12n - 1082)Combine common factors:   48n + 12n= 60n   18n^2 + 60n - 1083) Then factor: Since the number is too big to factor you have to take out the greatest common factor which is 6, because it goes into all the numbers, giving us: 6(3n^2+10n-18) 4) If you want to check then distribute       6(3n^2+10n-18)= 18n^2 + 48n + 12n - 108Hope that helped