a chemical formula based on analysis and molecular weightassume 100 g of this compoundmass N = 87.4 gmoles N = 87.4 g/ 14.0067 g/mol= 6.24mass H = 12.6 gmoles H = 12.6 g / 1.008 g/mol= 12.5the ratio is 12.5 / 6.24 = 2the empirical formula is NH2 ( molar mass =16.02 g/mol)d = molar mass x p / RTmolar mass unknown = 0.997 x 0.08206 x 373 K/ 0.934 atm =32.6 g/mol32.6 / 16.02 = 2multiply by 2 the empirical formula and the molecular formula is N2H4