1.  What is the equation of the line with slope 2/3 and passes through the midpoint of the segment joining points (-1, 6) and (-7, -4)?

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I can help with question #1:You can always find the equation of a straight line if you have these two items:a. the slope, which is usually shown as the letter "m"b. a point on the line.With these two items known, just use the following point-slope formula:y - y1 = m(x - x1), where (x1,y1) is the coordinates of the known point and m is the slope.In this problem you know m=2/3The coordinate of the known point (x1,y1) is a little tricky, but not too difficult to calculate.  It equals the midpoint of the segment with endpoints (-1,6) and (-7,4).The midpoint is simply the average of the x and y values of the endpoints.  For example, the x1 value equals (-1 + -7) ÷ 2 or (-8)/2 = - 4.  So x1= - 4.  Do the same thing to find y1, OK?Now just plug in x1, y1 and m into the point-slope equation above.  Finally solve for y ... that is, put y on one side of the equal sign and everything else on the other side.Hope that helps