calculate the mass of lead (II) chloride percipitate produced when 2.73g of sodium chloride in solution reacts in a double displacement reaction with excess aqueous lead(II) nitrate? plz help and thx 

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2NaCl+Pb(NO3)2----->2NaNO3+PbCl2Now you need to find the molar mass of:NaCl= 23+35 = 58g/mol NaClPbCl2= 207+(2*35) = 277g/mol PbCl2(2.73g NaCl)(1/58mol/g)= .047mol(0.047mol NaCl)(1mol PbCl2/2mol NaCl)(277g/mol PbCl2) =6.51g PbCl2Hope this helps!