How many L of 2M Mg(OH)2 mixes with 1.3L of .7M H2SO4 mixes with?

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When you balance the equation of the two reactants the coefficients of Mg(OH)2 and H2SO4 are both 1.  Assume both are strong acids and bases so both dissociate nearly 100%.  Then use stoichiometry1.3L*0.7 mol / L = 0.91 mol of H2SO4There is a 1:1 mole ratio from the balanced equation so you need 0.91 moles of Mg(OH)20.91 mol * 1 L/ 2.0 mol = 0.455 L of Mg(OH)2 needed