Quick Homework Help

# Airplane to seattle takes 198mph, the return trip takes 165mph. The total trip time was 5 hours. How far is Seattle? ⚑ Flag

by Jami014 at April 15, 2011

Jami -This is a rate-time-distance problem.  Here is the formula you need to remember for these problems:Rate x Time = DistanceRegardless how fast the plane is going, the "distance" traveled between the two airports is the same.Using our formula, take the words of the problem and insert the values like this:Rate x Time = Distance198 mph x T = D165 mph (5-T) = DThe problem states it takes 5 hours for the round trip, so if it takes T hours on the way to Seattle, then it must take (5-T) on the return trip, agree?Notice, as I mentioned above, both equations are equal to D, the distance traveled since it is the same distance in both directions.Since both are equal to D, why not set them equal to each other, right?198T = 165(5-T) = 825 - 165T198T + 165T = 825363T = 825T = 25/11 hoursNow, just plug this value for T into either one of the two equations, and you will get your answer for D, the distance.  I'll leave it for you to finish up the math.Hope that helps

Steve204 April 15, 2011

use d=rt to find that answer d is distance r is rate, and t is time

Blake087 April 15, 2011

Find the total time of the trip up and down by using T=D/sD=distance  S=speedD/198+D/165=5Solve for D

chitra003 April 16, 2011