what is the answer to the problem 4y^2-y+7

⚑ Flag

I'm guessing you have set this equal to zero.  If so: let a = 4;  b = -1; and c = 7.   See where these numbers came from?  Evaluate b^2 - 4ac You get -111.  This means your answer is an imaginary number because the solution = [(-b)+-SQR(b^2 - 4ac) ]/ 2a So you get:   [1 +- SQR(111) i] / 8 Note: SQR(-111) = SQR(-1) * SQR(111) = SQR(111) i because SQR(-1) = i , the imaginary number. Its imaginary because no number multiplied by itself = -1, however i^2 = -1 and i^4 = 1.  Do you see why?

when it's 0?