solve log[2](x-1) = 5 - log[2](x-3) for x

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I think the 2 is the base.log(x-1)+log(x-3)=5log(x-1)(x-3)=5(log property) The base of the log is 2which means 2^5=(x-1)(x-3)32=x^2-4x+3x^2-4x+29=0 factorise