2x + y - z = 0 x - y + z = 6 x + 2y + z = 3

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OH,OH,OH. Sorry, the question is exactly right, i made a mistake in my solve.It is my new solve:-2(x-y+z)=-12----> -2x+2y-2z=-12 so that: 2y=2x+2z-12and also we have: 2y+x+z=3 so thet:2y=3-x-zAs you know, we have: 2x+2z-12=3-x-z So that:3x+3z=15------> x+y=5we have x+z+2y=3, so: 2y=-2, so y = -12x+(-1)-z=0------> 2x-z=1                               x+z=5   so we have x=2we have 2+2(-1)+z=3---------->  z=3excuse me for my last rong solvement 

This is just a system of equations right?I think you can solve this problem using the elimination method pretty easily.2x + y - z = 0  x - y + z = 6When you add these equations together, you get x = 6.There, you have the x-value! Hope you can solve it from here, it just takes a little bit of substitution and thinking