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10y^3 + 20y^2 + 55y / 5y

Ronnie032

by Ronnie032 at March 09, 2011

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Hy  there.(10y^3+20y^2+55y)/5y = y(10y^2+20y+55)/5y = (10y^2+20y+55)/5 =   2y^2+4y+11I hope that you understand my solve.GOODLUCK

darklight darklight March 10, 2011

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dividing all the terms by 5y gives you 2y^2+4y+11

chitra003 chitra003 March 10, 2011

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2y^ + 4y + 11

udaysexy udaysexy March 11, 2011

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