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# so what is, log x + log (x+3) = 1? ⚑ Flag

by Snowflake at March 07, 2011

## Answers

Best Answer
Well the first thing you would want to do is recall the logarithmic properties. log x + log (x+3), when compressed according to the addition property of logarithms (forgot what exactly it was called), is log x(x+3). From here all you have to do is exponentiate (sorry....don't know any other words to describe the process, I remember a problem like this being worked out in my math book), which makes it: 10^log x(x+3) = 10^1. The log cancels out with 10, and you're left with x(x+3) = 10. I hope you can solve it from there, good luck!

Gentou March 08, 2011

logA+logB=logAB logx(x+1)=1 x(x+1)=10^1 solve for x

chitra003 March 08, 2011

Hi there.1) logA=B ---------> 10^B=A2) logA+logB= log(A+B)So that, we have log[x(x+3)]=1also we know from point 1 that, 10^1=x(x+3)so, x(x+3)=10 --------> x=2

darklight March 08, 2011

MRREEEOOOWWW!!!(ME NO LKE STUFF ME DON'T KNOW...........)

ChromeRedCat March 08, 2011

i dont know

...sydnie... March 09, 2011

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