Well the first thing you would want to do is recall the logarithmic properties. log x + log (x+3), when compressed according to the addition property of logarithms (forgot what exactly it was called), is log x(x+3). From here all you have to do is exponentiate (sorry....don't know any other words to describe the process, I remember a problem like this being worked out in my math book), which makes it: 10^log x(x+3) = 10^1. The log cancels out with 10, and you're left with x(x+3) = 10. I hope you can solve it from there, good luck!
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