boiling point elevation? 

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Okay, I can't exactly help you solve this problem because you didn't tell me the "thing" that's going to be put in the water. A nonelectrolytic solute isn't going to be enough.This is because when calculating colligative substances, I need to find the molarity and the molality of the substance.I'll just take sodium chloride as an example.Because NaCl has a molar mass of 58.5g/mol, therefore, it can be put in this equation: Molarity = Amount x Molarity of One in amount(500g/1) x (1/58.5g/mol) = 8.547 moles ( it could be as easy as 500g/58.5g/mol if you want it that way.)Then, we use this molarity to divide it by the amount of water, which is 300g to find the molality.So, 8.547/0.3 = 28.49 molals.Then, we multiply the Kb constant of water (0.51) and multiply it by the molals of NaCl we have.So, 0.51 x 28.49 = 14.5299°CNow all we got to do is to add this new temperature by the original boiling point of water. So 100 + 14.53 = 114.53°CTherefore, the new result is 114.53°C QED