a boat in calm seas travels in a straight line an dends the trip 16 kilometers west and 32 kilometers north of its original position. Find the distance of the trip to the nearest tenth of a kilometer
This is based on the quadratic equation: the ship travels sqrt(x^2+y^2), which is sqrt(16^2+32^2) which is sqrt(16^2 + (2*16)^2) = sqrt(16^2 + 4*16^2) = sqrt(5*16^2) = 16sqrt(5) = 35.77 so about 35.8km
If you are looking for distance, you just add them. So 48.0 kmOn the other hand if you are looking for displacement then use pythogareon theorem 16^2+32^2 .Then find the square root. The direction will be tan inverse of (32/16)
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