Find the rate of  2 cars traveling in the same direction they leave the same place the same time.the rate of 1 is twice as fast as other after 4 hrs the faster car is 80 miles ahead of the slower car.

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Let the speed (Rate of change in position) of 2nd car=xFirst car =2xAfter 4 hours, the first car covers 8x  milesand the second one 4x miles.8x=4x+80 (this is what given in the problem)solving for x=20mi/hrThe rate of first car=40mi/hrsecond car=20mi/hr