why are the x-intercepts positive two and three when the equation is negative? --> (x-2)(x-3)

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because the original equation is y= (x-2)(x-3) and to find the x-intercepts, you make y = 0. so the problem is (x-2)(x-3)= 0 you move the 2 and 3 to the other side and change signs, and you will get (3,0) (2,0)