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A steel ball of 0.250kg was thrown against a wall with a speed of 50.0 m\s. it reboundd straight back with a speed of 40.0m/s. if the ball was in contact in with wall wall for 0.100s,find the force

ken164

by ken164 at February 13, 2011

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First, calculate change in momentum.mv(after collision) - mv (initial)since change in momentum = change in time x Force, you divide by time and gain force.((0.250x50)-(0.250x40))/0.1 = 25

Andrey010 Andrey010 February 13, 2011

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Find the momentum of the ball=.25x50=12.5kgm/s Momentum after rebounding=.25x(-40)=-10kg m/s important , the velocity after rebound is negative Change in momentum=22.5kg m/s use the formula change in momentum=impulse 22.5=Fx.1   , solving for force=225N

chitra003 chitra003 February 14, 2011

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