A steel ball of 0.250kg was thrown against a wall with a speed of 50.0 m\s. it reboundd straight back with a speed of 40.0m/s. if the ball was in contact in with wall wall for 0.100s,find the force
First, calculate change in momentum.mv(after collision) - mv (initial)since change in momentum = change in time x Force, you divide by time and gain force.((0.250x50)-(0.250x40))/0.1 = 25
Find the momentum of the ball=.25x50=12.5kgm/s
Momentum after rebounding=.25x(-40)=-10kg m/s
important , the velocity after rebound is negative
Change in momentum=22.5kg m/s
use the formula change in momentum=impulse
22.5=Fx.1 , solving for force=225N