how do you find the coefficents for (x+3)^6  

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Or, in more detail:(x+3)^6 = (1)x^6 + (6C1)(3)(x^5) + (6C2)(3^2)(x^4) + (6C3)(3^3)(x^3) + (6C4)(3^4)(x^2) + (6C5)(3^5)(x) + (6C6)(3^6)where aCb = from a how many different ways of choosing b which is a!/(b![a-b]!)so 6C6 = 6!/(6!*0!) = 1and 6C3 = 6!/(3!*3!) = 20