Quick Homework Help

# how do I find the sq rt of a number like 163 that is not a perfect square ⚑ Flag

by Yolanda037 at February 09, 2011

we are working on determining if the points are collinear..here are my points P(9,6) Q (0,-3) R (3,1)

ok so we can use Newton's method of square roots:im going to guess that 13 is the correct answer:so the formula is: x sub(n+1) = x sub(n) - ((f(xsub(n))-num)/f ' (xsub(n)))so f(x) is x^2 because we are trying to find what number squared = 163f '(x) is 2xso my original will be 13 - (13^2-163/(2*13)) = 13 - (169-163/26) = 13 - .230 = 12.769and 12.769 will be your next xsub(n)

John_Doe February 09, 2011

Yolanda -I see you are an Algebra II student, so you probably don't have a clue what the previous solution meantI suggest something simple (if you don't have a calculator):(1) Find two perfect squares that "surround" your number. In your example:So 163 is surrounded by 144 & 169, agree? This means the square root of 163 must lie between 12 and 13, agree?(2) Determine where 163 falls within the range 144-169:There are 169-144 = 25 numbers in this range and 163 is 19 numbers beyond 144 so use 19/25 = 0.76.(3) Estimate of square root of 163 is:12 + 0.76 = 12.76.If you square this you get 162.8 ... not a bad estimate at all!Hope that helps

Steve204 February 09, 2011

http://xw2k.nist.gov/dads/HTML/squareRoot.html This is the way we used to do it in the 60's if we had no tables, or slide rule.   When we got to enough decimal places precision,we stopped

kroo_jteague February 09, 2011

The only way I know to find out the square root of a number that is not a perfect square is either to simplify it, or use a calculator.I also don't know whether or not 163 can be simplified, but I'm pretty sure you can't simplify it any further.

Gentou February 10, 2011