let f(x)=2/x-3 and g(x)=x squared-1Find an expression for f(g(x)) and five its domain.

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Dun werry, I have come. Its function stuffing: f(x) = 2 / (g(x)) -3 and g(x) = x squared So, f(x) really is 2 / (x squared) -3 Bottom of a fraction can never equal zero: so its domain is everywhere but -3 and 3. :D