How do I find the equation of a line passing through point (x,y) and that is perpendicular to another line (x-y=1)?

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First of all, a perpendicular line will have the negative reciprocal slope of the line that it is perpendicular to. Now, from x-y=1, you can solve that for y, which would make the equation into-y = -x+1y = x -1Now that you have your slope, get the negative reciprocal of 1.That would be -1.You have your slope. Now you want to find out the b value from y = mx + b, so plug in your slope and the points (x,y) into y = mx + b with the slope that you got:(y) = -1(x) + bOnce you solve for the b value, you will have all the information you need to plug into y= mx + b, and tada, you have your answer :D