Consider the curve x^3+3xy+y^2=5The equation of the tangent line to the curve at the point (1,1) has the form y=mx+b where m =  and b =

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Eden -Don't let this equation scare you ... first, find the slope (m) at the point (1,1).  Simply use implicit differentiation and solve for y'.  Here is the differentiation:implicit: Now, just plug in x=1 and y=1, then solve for y' which is the slope or m.Last step is to plug in the solution you found for y' into:y= mx + bAlso plug in  x=1 and y=1, then solve for b.  That's it ... wasn't that simple?Hope that helps