what is the mass in grams of 1.02*10^24 atoms manganese(Mn)?

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Okay, this is complicated, please pay attention:The atomic weight of a manganese atom is ~55. Hence, since the atomic number is 25, therefore,manganese has 30 neutrons. Protons weigh 1.673 *10^ -27 kilogramsSo 25x(1.673 *10^ -27)=4.182 *10^ -25 kilogramsNeutrons weigh 1.873 *10^ -27 kilogramsSo 30x(1.873 *10^ -27)=5.619 *10^ -25 kilogramsElectrons weigh 1/1280 of a proton. Atomic number equals to the amount of electrons as well.So 25x (1.307 *10^ -30)=3.267 *10^ -28 kilogramsNow if we add them all together it would be 9.804*10^ -25 kilograms.Now all we got to do is multiply by your desired number and we would get 1.00003523 kilograms.So therefore, 1.02*10^24 atoms of manganese is 1.00003523 kilograms.I'm sorry if this has to be so mathematical, but I do hope this answers your question. :)