Write an equation of a line that is parallel to y=2x-8 and passes through the point (6,2)?

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A line that is parallel to your line will have the same slope, so the required slope is 2  (in the y = mx + b form m is the slope).  Next, slope = the y change divided by the x change.  I'm assuming your correction to the point is makes it (6, -2).  Now: y-(-2) is y + 2 and that is the y change.  x -6 is the x change.  These two can be used to write a slope like this: (y + 2) / (x-6) = slope = 2 Multiply both sides by (x-6) Now you have:  y + 2 = 2(x-6) = 2x - 12 subtract 2 from both sides: y = 2x -14 is your equation.  You can see it has the same slope as your starting equation and if you substitute y = -2 and x = 6 into this new equation you will see -2 = -2, that is the equation works for the given point, thus the line passes through that point.