A line that is parallel to your line will have the same slope, so the required slope is 2 (in the y = mx + b form m is the slope). Next, slope = the y change divided by the x change. I'm assuming your correction to the point is makes it (6, -2). Now: y-(-2) is y + 2 and that is the y change. x -6 is the x change. These two can be used to write a slope like this:
(y + 2) / (x-6) = slope = 2
Multiply both sides by (x-6)
Now you have: y + 2 = 2(x-6) = 2x - 12
subtract 2 from both sides:
y = 2x -14 is your equation. You can see it has the same slope as your starting equation and if you substitute y = -2 and x = 6 into this new equation you will see -2 = -2, that is the equation works for the given point, thus the line passes through that point.