Use the given functions f and g to find the combinations (f+g)(x) and (f*g)(x) f(x)= x-3, g(x)= x^2-9

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(f+g)(x) is the same as f(x)+g(x). So... (x-3)+(x^2-9) = x^2 +x-12(fg)(x) = f(x)*g(x) → (x-3)(x^2-9) = x^3 - 3x^2 - 9x + 27