After a 2kg mass has slid 4m down from the top of a 20 degree inclined hill, what is its velocity [uk=.2]?

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Kinetic friction = uk * Ntherefore, 0.2 * 2kg*9.8 (cos 20) = 3.683595...F = ma[2kg*9.8 (sin 20)] - 3.683595... = 2*aa = 1.5v^2 = vo^2 +2a(displacement)v^2 = 2(1.5)(4m)v^2 = 12.08v = 3.5 m/s