Brightstorm Q & A : Find the perimeter of a rectangle whose length is 14 yeards and whose width is 40 ft.

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lqez now

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Lol.P= 2w+2lP=80+28P=108w is widthl is length. (:

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sukriti December 10, 2010

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Lol.P= 2w+2lP=80+28P=108w is widthl is length.(:

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sukriti December 10, 2010

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2(14)+2(40)=108 because perimeter of rectangle is 2l+2w=P w=width, l= lenght, P=perimeter

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GURUKID December 28, 2010

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