RNV -
Always remember that imaginary zeros happen in "conjugate pairs". So if (1-i) is a zero then so must be (1+i). So, the polynomial equation will be:
y=(x+4)[x-(1-i)][x-(1+i)]
Now just put this in standard form and you will have your answer!
Hope this helps
Imaginary Zeros occur in pairs ONLY when the coefficients are real integers. It is possible to have only 1 imaginary zero if the coefficients of the polynomial are imaginary. So, be careful here.
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