Quick Homework Help

# (b^3+6b^2-b-30)/(b-3) ⚑ Flag

by Allison088 at November 09, 2010

b^2+9b+26+(48/b-3)

fabianscorpio November 10, 2010

b^2 + 9b + 26 + (48/(b-3))

yankeekid November 10, 2010

Let's use synthetic division.  To do so, we write out the coefficients of our dividend, preceded by the r term of our divisor, written in the form x - r.  In this case, r = 3.  Once this is done, we bring down the first coefficient.  We multiply this term by r and write the product underneath the next coefficient.  We now multiply r by the new sum and again write the product underneath the next coefficient.  We follow this pattern until there are no more terms.  The bottom line (of sums) are the coefficients of our quotient (or depressed polynomial).  We would attach the variables with powers in descending order, starting with one degree less than the dividend.  Here's what it looks like: 3 |     1     6     -1    -30                 3    27     78          1     9    26     48We now attach the variables, starting with one degree less than the dividend (in this case, 2).  If there is a remainder, it is added over the divisor.Therefore, our quotient is b^2 + 9b + 26 + 48/(b-3)

Bill201 November 12, 2010