how would you graph f(x)=x^3 w/critical points?

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Ignore what yankee said.  The graph of an odd degree polynomial with a positive leading coefficient approaches negative infinity (or goes down) at its left end  and approaches positive infinity (or goes up) at its right end.  The only critical point is the origin, because it is the only real zero, and it is also a turning point.  Make a table of values: x |  y  -4 | -64-3 | -27-2 | -8  -1 | -1   0 |  0    1 |  1    2 |  8    3 | 27   4 | 64  This should be enough to graph your function.