A guy directly down the field for 35m before turning to the right at an angle of 25degree from his original direction and running additional 15m before stopping. What's the magnitude&displacement?

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Resolve the 15 meters into components. 15 sin(25) = 6.339 m right 15 cos(25) = 13.595 m down field add the 35 + 13.595 down field for 48.595 m downfield. Use Pythagorean theorem on these two legs of a right triangle to find the magnitude of the displacement. SQR(6.339^2 + 48.595^2) = 49.007 m The angle to the right of downfield is arcsine(6.339/49.007) or 7.43 degrees rotating right from the original direction.