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Find the value of k for which there is no term in the x^2 in the expansion of (1+kx)(2-x)^6

Tyler.

by Tyler. at September 13, 2010

This is an aice math question

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Since k is a constant so there is no k value that would change things (with the exception of 0... and with 0 it still doesnt work)... Unless you want k to be a function of x in which k = (-1/x) would work just fine

John_Doe John_Doe September 14, 2010

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