she sells coffee k for $6.20/lb and  coffee a for $5.80/lb. if she uses 18 lbs of coffee a in the blend and wishes to sell the mix at $6.10/lb, how many lbs of coffee k should she use.

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Okay, sweet. I just did this a few weeks ago in math.Here's how you set up the equation.:6.20k + (5.80 x 18) = 6.10 (18 + k)In this equation x means multiply, and k is pounds of coffee k. The 6.20k means $6.20 times k to find the total cost of coffee k. The $5.20 times 18 lbs is to find the total cost of coffee a.And lastly, 6.10 (18 + k) is the total cost of both mixtures together, since 6.10 is our average price and 18+k is the total pounds of coffee.Next, we'd go through the algebraic process, so:6.20k + (5.80 x 18) = 6.10 (18 + k)(Multiply through)6.20k + 104.4 = 109.8 + 6.10k(Combine variables to each side).10k = 5.4(Divide)k = 54SO. You need 54 pounds of coffee k.Hopefully that explanation helps (: