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a water rocket with a velocity of 48ft/sec. its height h,in feet,after t seconds is given by h=48t-16ft^2. after how many seconds with the height of the rocket be 20 feet?
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by Kelly265 at September 06, 2010

A water rocket is launched upward with an initail velocity of 48ft/sec. Its height h, in feet, after t seconds is given by h=48t-16^2. After how many seconds will the height of the rocket be 20 feet?

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-16t^2 + 48t -20-(16t^2 - 48t + 20)4(4t^2 - 12t + 5)(2t-1)(2t-5)At 0.5 and 2.5 seconds after he launch.

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yankeekid September 06, 2010

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a water rocket with a velocity of 48ft/sec. its height h,in feet,after t seconds is given by h=48t-16ft^2. after how many seconds with the height of the rocket be 20 feet? ⚑ Flag

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a water rocket with a velocity of 48ft/sec. its height h,in feet,after t seconds is given by h=48t-16ft^2. after how many seconds with the height of the rocket be 20 feet?
⚑ Flag