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factor 40x^4-80x^3+40x^2
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Kelly265

by Kelly265 at September 06, 2010

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Well immediately we can take 40x^2 out so that we are left with (40x^2)(x^2+2x+1). We then factor x^2+2x+1 to be (x+1)^2. so the final answer is 40*x*x*(x+1)*(x+1)
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John_Doe John_Doe September 06, 2010

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The work shown as an answer earlier was very close to being correct, however one small error was made in the factoring.After factoring out the 40x^2 ( x^2 - 2x + 1)The previous answer did not make the 2x a negative.This changes the final factoring to:40x^2 ( x-1) ( x - 1)40 xx (x-1)(x-1)
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Steve231 Steve231 September 06, 2010

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