This is related to Calculus as a way to find an instantaneous slope. f(x+h) is (x+h)^2 = x^2 +2xh + h^2. f(x) is x^2. The difference is 2xh +h^2. If you divide this by h you get 2x +h. As h approaches zero, the result (in the limit as they say) is 2x. Unless someone said to let h approach zero leave it as 2x + h.