Hi Ben -
Log differentiation is a GREAT tool when you have a messy rational function to deal with like you were given here. Let me show you how it works with a simpler example:
y = (2x + 3) / (x^2 -4)
Step 1: take natural log of both sides
ln(y) = ln[ (2x + 3) / (x^2 -4)]
Step 2: Dig out the cobwebs and use all the rules of logs that you learned in Algebra II or Pre-Calc.
ln(y) = ln(2x + 3) - ln(x^2 -4)
Step 3: Take derivative of each ln term with respect to x and don't forget to use "implicit" differentiation on y:
(1/y)(dy/dx) = [1/(2x + 3)](2) - [1/(x^2 -4)](2x)
Step 4: Multiply both sides of the equation by "y":
dy/dx = y{[1/(2x + 3)](2) - [1/(x^2 -4)](2x)}
Step 5: Substitute the original value for y on the right side of the equation:
dy/dx = [(2x + 3) / (x^2 -4)]{[1/(2x + 3)](2) - [1/(x^2 -4)](2x)}
I know this looks like a big mess, but it sure beats using the product and quotient rule on a messy differentiation problem like you were given.
Hope this helps