SIN^2(X) + SIN(x) = 2

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sin^2(x) + sin(x) -2 = 0(sin(x) - 1)(sin(x) + 2) = 0sin(x) = 1 or sin(x) = -2, but sin(x) is always less than or equal to 1 and greater than or equal to -1, so the only reasonable answer is sin(x) = 1.x is therefore 0 or any multiple of 2π radians.