(x+1) (x2-x+1)

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if this equals zero, then x=-1first, factor using the FOIL method to get 2x^2-x^2+x+2x-x+1then simplify to get x^2+2x+1Next, factor it out to get (x+1)(x+1)Finally, set (x+1) to zero and solve (since x+1 happens twice, you only need to set one of them to zero)Hopefully I'm right!