So for this problem you have to take out 2 first so it would be 2(1y to the third - 8z to the third). After that, use the formula (x³-y³)= {x-y}*{x²+xy+y²} or (x³+y³)= {x+y}*{x²-xy+y²}. The final answer is 2{y-2z}*{y²+2yz+4z²}.
Dont read the first one.First take out 2 first so it would be 2(y cube - 8 z cube). For these kind of questions you could use the formulas: (x cube - y cube)= {x-y}*{x square+xy + y square} or (x cube +y cube)= {x+y}*{x square-xy+y square}. The final answer is: 2{y-2z}*{y square+2yz+4z square}.
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