a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 l solution that is 50% chlorine?

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x = 60% chlorinated 100-x = 40% chlorinated .6x + .4(100-x) = .5(100) .6x + 40 - .4x = 50 .2x = 10 x = 50 therefore, 50(units) of 60% chlorinated, and 50(units) of 40% chlorinated