(x-2)/(x+1) + (x-5)/(x+2) = 2 The answer is -13/10 how to get that? steps please

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Hi!You need to start by finding the common denominator for the expressions on the left-hand side of the equation.The simplest way is to multiply the first fraction by (x+2) and the second fraction by (x+1). Remember to multiply both the numerator and denominator by this! It looks like this:(x-2)*(x+2) / (x+1)*(x+2) + (x-5)*(x+1) / (x+2)*(x+1) = 2If you do all the multiplications for this, you get:(x^2 - 4 + x^2 - 4x - 5) / (x^2 + 3x + 2) = 2Then you move x^2 + 3x + 2 over to the other side of the equation by multiplying with this on both sides. So you get:x^2 - 4 + x^2 - 4x - 5 = 2x^2 + 6x + 4Use regular math calculation to get:2x^2 - 4x - 9 = 2x^2 + 6x + 4Now, move all terms containing x to the left-hand side of the equation and the others to the right-hand side:2x^2 - 2x^2 - 4x - 6x = 4 + 9Then you're left with -10x = 13 which means that x = -13/10