To find the inverse you switch y with x so you start off with:x = (5y-1) / (2y+3) Then you solve for y.x(2y+3) = 5y-12xy+3x = 5y-1 Rearrange so that you get terms containing y on one side and the rest on the other:2xy - 5y = -1-3xy(2x-5) = -1-3x→ f^-1(x) = (-1-3x) / (2x-5)