let a be the first numberr be common differencen be the no. of termsar^(n-1) = tnthus, 1/36 times r^(5-1) = 9/4or, r^4 = 9 times 36/4or, r^4 = 9 times 9 or, r^4 = 3^4thus r = 31st term = 1/362nd term = 1/36 times 3 = 1/123rd term = 1/times time 3 = 1/44th term = 1/4 times 3 = 3/45th term(given) = 3/4 times 3 = 9/4thus, the pattern fits and we're correctthe 3 required numbers are :1/12, 1/4 and 3/4