two pipes fill a storage tank in 9 hours. the smaller pipe takes 3 times as long to fill the tank as the larger pipe. how long would it take the larger pipe to fill the tank alone?

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i think i messed up with the answer below. so here is the correct solution :let smaller pipe be x and bigger pipe be yx=y/3 ( as smaller takes 3 times as long)(x+y) can fill 1 tank in 9 hrs.(y/3+y) can fill 1 tank in 9 hrs (substitute x=y/3)(4y/3) can fill 1 tank in 9 hrs. ( jus adding y/3 and y)thus, y can full 1 tank in 9 times 4/3 = 12 hrsTherefore, it will take 12 hrs for the larger pipe to fill the tank alone.