What is the solution set for the equation: 4(3x-2)squared=36?

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You have to find the value of x here.4(3x-2)^2 = 36(3x-2)^2 = 36/4(3x-2)^2= 9(3x-2)^2 = (±3)^2  ( note here that even -3 squared is 9)3x - 2 = ±33x = (+3 + 2 ) or (-3 + 2)3x = 5 or -1thus, x = 5/3 or -1/3